Eureka Math Grade 4 Module 5 Lesson 29 Answer Key (2024)

Engage NY Eureka Math 4th Grade Module 5 Lesson 29 Answer Key

Eureka Math Grade 4 Module 5 Lesson 29 Problem Set Answer Key

Question 1.
Estimate each sum or difference to the nearest half or whole number by rounding. Explain your estimate using words or a number line.
a. 2\(\frac{1}{12}\) + 1\(\frac{7}{8}\) ≈ ____40/12________

Answer:
2(1/12) + 1(7/8) = 40/12.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
2(1/12) + 1(7/8).
12 x 2 = 24.
1 x 8 = 8.
24 + 1/12 = 25/12.
8 + 7/8 = 15/8.
25/12 + 15/8 = 40/12.

b. 1\(\frac{11}{12}\) + 5\(\frac{3}{4}\) ≈ ____46/4_________

Answer:
1(11/12) + 5(3/4) = 46/4.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
1(11/12) + 5(3/4).
12 x 1 = 12.
5 x 4 = 20.
12 + 11/12 = 23/12.
20 + 3/4 = 23/4.
23/12 + 23/4 = 46/4.

c. 8\(\frac{7}{8}\) – 2\(\frac{1}{9}\) ≈ ____52/9________

Answer:
8(7/8) – 2(1/9) = 52/9.

Explanation:
In the above-given question,
given that,
Estimate each difference to the nearest half.
8(7/8) – 2(1/9).
8 x 8 = 64.
2 x 9 = 18.
64 + 7/8 = 71/8.
18 + 1/9 = 19/9.
71/8 – 19/9 = 52/9.

d. 6\(\frac{1}{8}\) – 2\(\frac{1}{12}\) ≈ __________

Answer:
6(1/8) – 2(1/12) = 24/12.

Explanation:
In the above-given question,
given that,
Estimate each difference to the nearest half.
6(1/8) – 2(1/12).
6 x 8 = 48.
2 x 12 = 24.
48 + 1/8 = 49/8.
24 + 1/12 = 25/12.
49/8 – 25/12 = 24/12.

e. 3\(\frac{3}{8}\) + 5\(\frac{1}{9}\) ≈ _____73/9______

Answer:
3(3/8) + 5(1/9) = 73/9.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
3(3/8) + 5(1/9).
8 x 3 = 24.
5 x 9 = 45.
24 + 3/8 = 27/8.
45 + 1/9 = 46/9.
27/8 + 46/9 = 73/9.

Question 2.
Estimate each sum or difference to the nearest half or whole number by rounding. Explain your estimate using words or a number line.
a. \(\frac{16}{5}\) + \(\frac{11}{4}\) ≈ ______

Answer:
16/5 + 11/4 = 6.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
16/5 + 11/4.
16/5 = 3.2.
11/4 = 2.75.
3.2 + 2.75 = 5.95.
16/5 + 11/4 = 5.95.

b. \(\frac{17}{3}\) – \(\frac{15}{7}\) ≈ _______

Answer:
17/3 + 15/7 = 8.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
17/3 + 15/7.
17/3 = 5.6.
15/7 = 2.14.
5.6 + 2.14 = 7.74.
17/3 + 15/7 = 7.74.

c. \(\frac{59}{10}\) + \(\frac{26}{10}\) ≈ _______

Answer:
59/10 + 26/10 = 8.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
59/10 + 26/10.
59/10 = 5.9.
26/10 = 2.6.
5.9 + 2.6 = 8.5.
59/10 + 26/10 = 8.

Question 3.
Montoya’s estimate for 8\(\frac{5}{8}\) – 2\(\frac{1}{3}\) was 7. Julio’s estimate was 6\(\frac{1}{2}\). Whose estimate do you think is closer to the actual difference? Explain.

Answer:
8(5/8) -2(1/3) = 62/5.

Explanation:
In the above-given question,
given that,
Estimate each difference to the nearest half.
8(5/8) – 2(1/3).
8 x 8 = 64.
2 x 3 = 6.
64 + 5/8 = 69/8.
6 + 1/3 = 7/3.
69/8 – 7/3 = 62/5.

Question 4.
Use benchmark numbers or mental math to estimate the sum or difference.
a. 14\(\frac{3}{4}\) + 29\(\frac{11}{12}\)

Answer:
14(3/4) + 29(11/12) = 418/12.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
14(3/4) + 29(11/12).
14 x 4 = 56.
29 x 12 = 348.
56 + 3/4 = 59/4.
348 + 11/12 = 359/12.
59/4 + 359/12 = 418/12.

b. 3\(\frac{5}{12}\) + 54\(\frac{5}{8}\)

Answer:
3(5/12) + 54(5/8) = 478/12.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
3(5/12) + 54(5/8).
12 x 3 = 36.
54 x 8 = 432.
36 + 5/12 = 41/12.
432 + 5/8 = 437/8.
41/12 + 437/8 = 478/12.

c. 17\(\frac{4}{5}\) – 8\(\frac{7}{12}\)

Answer:
17(4/5) – 8(7/12) = 192/60.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
17(4/5) – 8(7/12).
17 x 5 = 85.
12 x 8 = 96.
85 + 4/5 = 89/5.
96 + 7/12 = 103/12.
89/5 + 103/12 = 192/60.

d. \(\frac{65}{8}\) – \(\frac{37}{6}\)

Answer:
65/8 – 37/6 = 4.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
65/8 – 37/6.
65/8 = 8.1.
37/6 = 6.1.
8.1 – 6.1 = 4.1.
65/8 – 37/6 = 4.1.

Eureka Math Grade 4 Module 5 Lesson 29 Exit Ticket Answer Key

Estimate each sum or difference to the nearest half or whole number by rounding. Explain your estimate using words or a number line.
Question 1.
2\(\frac{9}{10}\) + 2\(\frac{1}{4}\) ≈ _________

Answer:
2(9/10) + 2(1/4) = 38/40.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
2(9/10) + 2(1/4).
2 x 10 = 20.
2 x 4 = 8.
20 + 9/10 = 29/10.
8 + 1/4 = 9/4.
29/10 + 9/4 = 38/40.

Question 2.
11\(\frac{8}{9}\) – 3\(\frac{3}{8}\) ≈ _________

Answer:
11(8/9) – 3(3/8) = 80/72.

Explanation:
In the above-given question,
given that,
Estimate each difference to the nearest half.
11(8/9) – 3(3/8).
11 x 9 = 99.
3 x 8 = 24.
99 + 8/9 = 107/9.
24 + 3/8 = 27/8.
107/9 – 27/8 = 80/72.

Eureka Math Grade 4 Module 5 Lesson 29 Homework Answer Key

Question 1.
Estimate each sum or difference to the nearest half or whole number by rounding. Explain your estimate using words or a number line.
a. 3\(\frac{1}{10}\) + 1\(\frac{3}{4}\) ≈ ___________

Answer:
3(1/10) + 1(3/4) = 38/40.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
3(1/10) + 1(3/4).
10 x 3 = 30.
1 x 4 = 4.
30 + 1/10 = 31/10.
4 + 3/4 = 7/4.
31/10 + 7/4 = 38/40.

b. 2\(\frac{9}{10}\) + 4\(\frac{4}{5}\) ≈ __________

Answer:
2(9/10) + 4(4/5) = 53/50.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
2(9/10) + 4(4/5).
2 x 10 = 20.
5 x 4 = 20.
20 + 9/10 = 29/10.
20 + 4/5 = 24/5.
29/10 + 24/5 = 53/50.

c. 9\(\frac{9}{10}\) – 5\(\frac{1}{5}\) ≈ __________

Answer:
9(9/10) – 5(1/5) = 73/5.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
9(9/10) – 5(1/5).
9 x 10 = 90.
5 x 5 = 25.
90 + 9/10 = 99/10.
25 + 1/5 = 26/5.
99/10 – 26/5 = 73/5.

d. 4\(\frac{1}{9}\) – 1\(\frac{1}{10}\) ≈ __________

Answer:
4(1/9) – 1(1/10) = 48/10.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
4(1/9) – 1(1/10).
9 x 4 = 36.
1 x 10 = 10.
36 + 1/9 = 37/9.
10 + 1/10 = 11/10.
37/9 + 11/10 = 48/10.

e. 6\(\frac{3}{12}\) + 5\(\frac{1}{9}\) ≈ _______

Answer:
6(3/12) + 5(1/9) = 121/9.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
6(3/12) + 5(1/9).
6 x 12 = 72.
5 x 9 = 45.
72 + 3/12 = 75/12.
45 + 1/9 = 46/9.
75/12 + 46/9 = 121/9.

Question 2.
Estimate each sum or difference to the nearest half or whole number by rounding. Explain your estimate using words or a number line.
a. \(\frac{16}{3}\) + \(\frac{17}{8}\) ≈ __________

Answer:
16/3 + 17/8 = 7.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
16/3 + 17/8.
16/3 = 5.3.
17/8 = 2.1.
5.3 + 2.1 = 7.4.
16/3 + 17/8 = 7.

b. \(\frac{17}{3}\) – \(\frac{15}{4}\) ≈ __________

Answer:
17/3 – 15/4 = 9.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
17/3 – 15/4.
17/3 = 5.6.
15/4 = 3.7.
5.6 + 3.7 = 9.3.
15/4 + 17/3 = 9.

c. \(\frac{57}{8}\) + \(\frac{26}{8}\) ≈ __________

Answer:
57/8 + 26/8 = 10.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
57/8 + 26/8.
57/8 = 7.1.
26/8 = 3.2.
7.1 + 3.2 = 10.3.
57/8 + 26/8 = 10.

Question 3.
Gina’s estimate for 7\(\frac{5}{8}\) – 2\(\frac{1}{2}\) was 5. Dominick’s estimate was 5\(\frac{1}{2}\). Whose estimate do you think is closer to the actual difference? Explain.

Answer:
7(5/8) – 2(1/2) = 56/4.

Explanation:
In the above-given question,
given that,
Estimate each difference to the nearest half.
7(5/8) – 2(1/2).
8 x 7 = 56.
2 x 2 = 4.
56 + 5/8 = 61/8.
4 + 1/2 = 5/2.
61/8 – 5/2 = 56/4.

Question 4.
Use benchmark numbers or mental math to estimate the sum or difference.
a. 10\(\frac{3}{4}\) + 12\(\frac{11}{12}\)

Answer:
10(3/4) + 12(11/12) = 199/3.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
10(3/4) + 12(11/12).
10 x 4 = 40.
12 x 12 = 144.
40 + 3/4 = 43/4.
144 + 11/12 = 156/12.
43/4 + 156/12 = 199/3.

b. 2\(\frac{7}{10}\) + 23\(\frac{3}{8}\)

Answer:
2(7/10) + 23(3/8) = 214/80.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
2(7/10) + 23(3/8).
2 x 10 = 20.
23 x 8 = 184.
20 + 7/10 = 27/10.
184 + 3/8 = 187/8.
27/10 + 187/8 = 214/80.

c. 15\(\frac{9}{12}\) – 8\(\frac{11}{12}\)

Answer:
15(9/12) – 8(11/12) = 82/12.

Explanation:
In the above-given question,
given that,
Estimate each difference to the nearest half.
15(9/12) – 8(11/12).
15 x 12 = 180.
8 x 12 = 96.
180 + 9/12 = 189/12.
96 + 11/12 = 107/12.
189/12 – 107/12 = 82/12.

d. \(\frac{56}{7}\) – \(\frac{31}{8}\)

Answer:
56/7 – 31/8 = 4.2.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
56/7 – 31/8.
56/7 = 8.
31/8 = 3.8.
8 – 3.8 = 4.2.
56/7 – 31/8 = 4.2.

Eureka Math Grade 4 Module 5 Lesson 29 Answer Key (2024)

FAQs

What grade does Eureka math go up to? ›

Eureka Math® is a holistic Prekindergarten through Grade 12 curriculum that carefully sequences mathematical progressions in expertly crafted modules, making math a joy to teach and learn. We provide in-depth professional development, learning materials, and a community of support.

What are the four core components of a Eureka Math TEKS lesson? ›

A typical Eureka lesson is comprised of four critical components: fluency practice, concept development (including a problem set), application problem, and student debrief (including the Exit Ticket).

Is Eureka Math a curriculum? ›

An Elementary, Middle, And High School Math Curriculum. Eureka Math® is a math program designed to advance equity in the math classroom by helping students build enduring math knowledge.

What is the purpose of the concept development in Eureka math? ›

The concept development is generally comprised of carefully sequenced problems centered within a specific topic to begin developing mastery via gradual increases in complexity.

What's the hardest math class? ›

1. Real Analysis: This is a rigorous course that focuses on the foundations of real numbers, limits, continuity, differentiation, and integration. It's known for its theoretical, proof-based approach and can be a paradigm shift for students used to computation-heavy math courses.

What is the highest math class ever? ›

Math 55 is a two-semester freshman undergraduate mathematics course at Harvard University founded by Lynn Loomis and Shlomo Sternberg. The official titles of the course are Studies in Algebra and Group Theory (Math 55a) and Studies in Real and Complex Analysis (Math 55b).

Is Eureka Math scripted? ›

Eureka Math is scripted for the teacher and anticipates student responses, which is very useful for studying in advance. This makes each module easy to follow and easy to understand what is expected.

Is Eureka math TEKS aligned? ›

This Field User Guide was developed to support the use of the High Quality Instructional Materials (HQIM) Eureka Math TEKS Edition (K-5)-aligned instructional materials to provide specially designed instruction (SDI) for students with disabilities as required through IDEA (2004).

How many states use Eureka math? ›

We wrote EngageNY Math, and over time we developed that program into Eureka Math. The original OER curriculum is available on the EngageNY and Great Minds sites for free, and it has been downloaded over 13 million times by users in all 50 states, making Eureka Math the most widely used K–5 math program in the country.

Is Eureka Math good or bad? ›

Is Eureka Math a good curriculum? The answer to this question depends on the target audience. If you're a teacher in a public school who needs to cover State Standards and your goal is merely to prepare students for State tests, then Eureka may be a good curriculum for you.

Is Eureka Math still free? ›

Eureka Math Is Free

The curriculum is accompanied by a selection of instructional materials and support resources for teachers at no additional cost.

What are teachers saying about Eureka Math? ›

“The difference for teachers with Eureka Math2 is they have a better understanding of how to teach kids to think about math. That's what they've learned with the manual. They're not just teaching a concept or skill. They're teaching the thinking that helps students attack a concept or skill,” says May.

What is the structure of the Eureka math lesson? ›

Each lesson in Eureka Math TEKS Edition is structured to incorporate fluency activities along with the development of conceptual understanding, procedural skills, and problem solving. These components are taught through the deliberate progression of material from concrete to representational to abstract.

What is the UDL in Eureka math? ›

Universal Design for Learning in Eureka Math2

The authors of Eureka Math2 applied the UDL Guidelines to develop lessons that provide multiple means of engagement, representation, and action and expression.

Who is the father of math Eureka? ›

Sometimes called the father of mathematics and mathematical physics, Archimedes had a wide influence on mathematics and science.

What is the highest level of math in 9th grade? ›

9th grade math usually focuses on Algebra I, but can include other advanced mathematics such as Geometry, Algebra II, Pre-Calculus or Trigonometry.

What is the hardest math in 5th grade? ›

Some of the hardest math problems for fifth graders involve multiplying: multiplying using square models, multiplying fractions and whole numbers using expanded form, and multiplying fractions using number lines.

What is 8th grade advanced math? ›

Students on the advanced math track will take Algebra. This standards-based class covers the second half of Math 8 as well as high school-level Algebra I and is designed to prepare students for geometry in ninth grade. Placement is based on prior grades, teacher recommendations, and district benchmark testing scores.

What grade level does prodigy math go up to? ›

Prodigy Math Game features more than 1,500 mathematical skills, aligned with curriculum standards for grades 1 to 8.

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